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> Matematica, bat-o vina

Andy_ACS
post 22 Feb 2010, 21:41
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QUOTE(vis-a-vis @ 22 Feb 2010, 18:43)
Sa vezi in ce stil calculeaza cate unii pretul cu tot cu TVA... 04.gif
*



Ete aici biggrin.gif :


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vis-a-vis
post 22 Feb 2010, 21:42
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Bun asa radmasa.gif


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SiloS
post 4 Mar 2010, 22:53
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Ridic o noua problema:

Se da o bara de densitate necunoscuta notata "d", de lungime X si cu diametrul de 60mm.
Se mai da inca o bara din acelasi material si cu aceeasi lungime ca prima, dar cu diametrul de 100mm.
Cu cat la suta este mai grea bara de 100mm fata de cea de 60mm ?


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vi_escu
post 4 Mar 2010, 23:24
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177.77%, acolo unde exista camp gravitational. Altfel 0.


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Markos
post 4 Mar 2010, 23:36
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Pai greutatea este direct proportionala cu masa, deci cu volumul si cu densitatea. Densitatea barelor fiind aceiasi, ramane volumul. Lungimea fiind aceeasi, ramane aria sectiunii. Aria este direct proportionala cu patratul diametrului.

Ar iesi ca (A1-A2)/A2 = A1/A2 - 1 = (D1/D2)2 - 1 = (100/60)2 - 1 = 1,(7)

Deci aia de 100 este mai grea cu 177,(7)%

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This post has been edited by Markos: 4 Mar 2010, 23:40


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SiloS
post 4 Mar 2010, 23:42
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Aha. Multumesc mult pentru rezolvare.
@Markos, multumesc mult, nu stiam ca "Aria este direct proportionala cu patratul diametrului.".


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Markos
post 4 Mar 2010, 23:46
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Pai da, fiind vorba despre o sectiune circulara, aria este egala cu pipepatru de inmultit cu patratul diametrului.


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Asi
post 4 Mar 2010, 23:48
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consideram o acceleratie gravitationala constanta, deci din relatia G=m*g, G~m (direct proportional).
Cum densitatea "d" (sau ro as zice eu) este constanta, din relatia m=ro*V => m~V
Iar cum V=A*L (aria*lungime) iar lungimea este constanta (ipoteza) => V~A
Iar aria A=pi*r^2, unde pi este o constanta => A~r^2
Adica ajungem la G~r^2

Asadar pentru aflarea diferentei procentuale (care este proportionala cu oricare marime de greutate, masa, volum, arie, sau patratul razei) este suficient sa fac diferenta procentuala doar uneia dintre marimi. (patratul razei in acest caz)

Adica r^2, 10000 fata de 3600, adica 10000*100/3600=277,(7)% fata de bara mai subtire
si cu 177,(7)% mai grea

qed

This post has been edited by Asi: 4 Mar 2010, 23:51


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vi_escu
post 4 Mar 2010, 23:53
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Bre Asi, omul a intrebat "cu cat la suta" nu "de cate ori" (si asta exprimat in procente nedumerire.gif ), sesizezi difenta? Vezi ca ai gresit, derutezi omu' si ramane fisu' repetent.

Daca tot ai editat, corecteaza pana la capat.

This post has been edited by vi_escu: 4 Mar 2010, 23:57


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Marty
post 5 Mar 2010, 10:13
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Ba nene, daca era cu baruri, stiam! Cu bare... habar n-am!


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vi_escu
post 5 Mar 2010, 10:21
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Stai frate ca adaptam problema: unul bea mastica prima cu un pahar cu diametrul de 60mm, altu' cu 100mm, bla, bla. Asa mai vii de-acasa, nu?


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ady77
post 5 Mar 2010, 10:28
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Ala de bea cu 60 mm e mai fraier? rolleyes.gif


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vi_escu
post 5 Mar 2010, 11:28
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depinde cine plateste


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ady77
post 5 Mar 2010, 11:33
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Copos? wink.gif


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Victoras2001
post 5 Mar 2010, 11:37
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QUOTE(SiloS @ 4 Mar 2010, 22:53)
Ridic o noua problema:

Se da o bara de densitate necunoscuta notata "d", de lungime X si cu diametrul de 60mm.
Se mai da inca o bara din acelasi material si cu aceeasi lungime ca prima, dar cu diametrul de 100mm.
Cu cat la suta este mai grea bara de 100mm fata de cea de 60mm ?
*


N-ai incercat sa rogi pe cineva sa ti le dea pe carca? Nu de alta, da aflai imediat diferenta de greutate. tongue.gif


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bucatzel
post 5 Mar 2010, 11:42
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QUOTE
Ala de bea cu 60 mm e mai fraier?


nu, are mana mai mica biggrin.gif

This post has been edited by bucatzel: 5 Mar 2010, 11:43


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ady77
post 5 Mar 2010, 11:49
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Eu credeam ca are probleme cu sorbu' biggrin.gif


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MihaiD
post 5 Mar 2010, 12:24
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Am si eu o nepotica care m-a rugat sa o ajut la o problema(vad ca sunt matematicieni pe forum, poate o rezolva ei)...

Care sunt solutiile ecuatiei urmatoare 44841203.jpg daca n=5 ?
(x,y,z sunt numere întregi nenule)

This post has been edited by MihaiD: 5 Mar 2010, 12:26


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Marty
post 5 Mar 2010, 12:27
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Auzi ma, nu stiu raspunsu' la intrebarea ta, da' din cauza neapoata-tii era sa-mi pierd serviciu'. I-auzi vorba la ei: "va rugam sa va rezumati la problemele de serviciu!"


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vi_escu
post 5 Mar 2010, 12:35
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Ado la noi c-o rezolvam imediat. Pe nepoata.

This post has been edited by vi_escu: 5 Mar 2010, 15:32


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ady77
post 5 Mar 2010, 12:41
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QUOTE(vi_escu @ 5 Mar 2010, 12:35)
Trimite-o la mine sa-i arat socoteala, sigur iese si solutia.
*


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Markos
post 5 Mar 2010, 12:47
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îi explic io personal partea aia cu "igrec la puterea en"


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GIC
post 5 Mar 2010, 12:57
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Io as pune-o sa rezolve problema cu bara!

This post has been edited by GIC: 5 Mar 2010, 12:58


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b76bgaarh
post 5 Mar 2010, 13:03
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cam nasol daca are aceeasi lungime.....


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Asi
post 6 Mar 2010, 18:00
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QUOTE(MihaiD @ 5 Mar 2010, 12:24)
Am si eu o nepotica care m-a rugat sa o ajut la o problema(vad ca sunt matematicieni pe forum, poate o rezolva ei)...

Care sunt solutiile ecuatiei urmatoare 44841203.jpg daca n=5 ?
(x,y,z sunt numere întregi nenule)
*




Pai tocmai ce-a zis fermat ca nu exista, pentru orice n>2 (de la 3 incolo).

http://en.wikipedia.org/wiki/Fermat%27s_Last_Theorem


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nalodaniel
post 6 Mar 2010, 18:14
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good job biggrin.gif

asta e mai mult de fizica, si m-am cam ciondanit cu niste colegi participanti la faza nationala a olimpiadei de fizica (ultima mea olimpiada a fost faza mucipala la religie ), pana la urma am aflat solutia de la prof; va dau problema ca material de gandire:

doua bile de aceleasi dimensiuni si acelasi material sunt eliberate simultan de la acceasi inaltime.
una din bile are o gaura in centru, deci este mai usoara.

care bila ajunge prima jos?

This post has been edited by nalodaniel: 6 Mar 2010, 19:01


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Andy_ACS
post 6 Mar 2010, 18:52
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QUOTE(nalodaniel @ 6 Mar 2010, 18:14)
doua bile de acceasi forma
*



era culmea sa fie bile de forme diferite smile.gif

se da drumul la ambele simultan?

Bafta!


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nalodaniel
post 6 Mar 2010, 19:00
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a3a oara scriu corect


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a... corect la faza cu bilele laugh.gif
normal ca se dau drumul in acelasi timp tongue.gif

This post has been edited by nalodaniel: 6 Mar 2010, 19:00


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Andy_ACS
post 6 Mar 2010, 19:02
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Pai eu cred ca bila plina ajunge prima. Deoarece are masa mai mare fata de cealalta, implicit greutatea mai mare. Insa dau raspunsul asta mai mult asa babeste smile.gif

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nalodaniel
post 6 Mar 2010, 19:06
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a3a oara scriu corect


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asta am zis si eu colegilor.

daar

in formula se anuleaza reciproc masele, si acceleratia ramane acceleratia gravitationala smile.gif


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